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1.57x^2-4x+2=0
a = 1.57; b = -4; c = +2;
Δ = b2-4ac
Δ = -42-4·1.57·2
Δ = 3.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-\sqrt{3.44}}{2*1.57}=\frac{4-\sqrt{3.44}}{3.14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+\sqrt{3.44}}{2*1.57}=\frac{4+\sqrt{3.44}}{3.14} $
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